1/x+3=2x/x^2-5

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Solution for 1/x+3=2x/x^2-5 equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

1/x+3 = (2*x)/(x^2)-5 // - (2*x)/(x^2)-5

1/x-((2*x)/(x^2))+3+5 = 0

1/x-2*x^-1+3+5 = 0

-1*x^-1 = -8 // : -1

x^-1 = 8

-1 < 0

1/(x^1) = 8 // * x^1

1 = 8*x^1 // : 8

1/8 = x^1

x = 1/8

x = 1/8

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